The solubility product of a sulphide $MS$ is $3 \times 10^{-25}$ and that of another sulphide $NS$ is $4 \times 10^{-40}$. In an ammoniacal solution,which of the following occurs?
- AOnly $NS$ gets precipitated
- BOnly $MS$ gets precipitated
- CNo sulphide precipitates
- DBoth sulphides precipitate
Explore More
Similar Questions
Solubility of calcium phosphate (molecular mass,$M$) in water is $W \ g$ per $100 \ mL$ at $25^{\circ} C$. Its solubility product at $25^{\circ} C$ will be approximately.
DifficultJEE MAIN 2024
View SolutionSolubility of a salt $A_2B_3$ is $1 \times 10^{-3} \ mol \ dm^{-3}$. What is the value of its solubility product?
The solubility of sparingly soluble salts $MX$, $MX_2$ and $MX_3$ is $1 \times 10^{-3} \text{ mol/L}$. Hence, their respective solubility products are
DifficultMHT CET 2026
View SolutionSolubility of a salt $M_2X_3$ is $y \ mol \ dm^{-3}$. The solubility product of the salt will be
DifficultIIT 1990
View SolutionThe solubility of a salt $A_2B_3$ is $10^{-3} \ M$. What will be its solubility product?
Easy
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo