Solve the following pair of equations by the | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Given equations are:$(1) \ 11x + 13y = 61$$(2) \ 13x + 11y = 59$Adding equations $(1)$ and $(2)$:$(11x + 13x) + (13y + 11y) = 61 + 59$$24x + 24y =

Vedclass · Accepted Answer

$(2, 3)$

Vedclass · Answer

(D) Given equations are:$(1) \ 11x + 13y = 61$$(2) \ 13x + 11y = 59$Adding equations $(1)$ and $(2)$:$(11x + 13x) + (13y + 11y) = 61 + 59$$24x + 24y = 120$Dividing by $24$:$x + y = 5$  --- $(3)$Subtracting equation $(1)$ from $(2)$:$(13x - 11x) + (11y - 13y) = 59 - 61$$2x - 2y = -2$Dividing by $2$:$x - y = -1$ --- $(4)$Adding equations $(3)$ and $(4)$:$(x + y) + (x - y) = 5 + (-1)$$2x = 4 \implies x = 2$Substituting $x = 2$ in equation $(3)$:$2 + y = 5 \implies y = 3$Thus,the solution is $(x, y) = (2, 3)$.

Solve the following pair of equations by the method of elimination:
$11x + 13y = 61$
$13x + 11y = 59$

Similar Questions

Solve the following pairs of equations by reducing them to a pair of linear equations:
$\frac{7x - 2y}{xy} = 5$
$\frac{8x + 7y}{xy} = 15$

Solve the following pair of linear equations:
$ax + by = c$
$bx + ay = 1 + c$

If $x=a$ and $y=b$ is the solution of the equations $x-y=2$ and $x+y=4,$ then the values of $a$ and $b$ are,respectively:

Solve the following pairs of equations by the method of elimination:
$7(y+3)-2(x+2)=14$
$4(y-2)+3(x-3)=2$

For a pair of equations $9x - 4y = 14$ and $7x - 3y = 11$,find the value of $y$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Solve the following pair of equations by the method of elimination:$11x + 13y = 61$$13x + 11y = 59$