Solve the following system of inequalities graphically: $x < 1, y < 0, x \geq -3, x + y \geq 0$.

(N/A) To solve the system of inequalities graphically,we consider the corresponding equations:
$1$. $x = 1$ (Vertical line passing through $(1, 0)$,shade to the left).
$2$. $y = 0$ (The $x$-axis,shade below the line).
$3$. $x = -3$ (Vertical line passing through $(-3, 0)$,shade to the right).
$4$. $x + y = 0$ or $y = -x$ (Line passing through $(0, 0)$ and $(1, -1)$,shade above the line).
The solution region is the intersection of these four half-planes. The vertices of the resulting region are $(-3, 3)$,$(-3, 0)$,and $(1, -1)$.