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(B) To solve the system of linear equations:$I.$ $7x - 3y = 13$$II.$ $5x + 4y = 40$Multiply equation $(I)$ by $4$ and equation $(II)$ by $3$ to elimin

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if $x < y$

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(B) To solve the system of linear equations:$I.$ $7x - 3y = 13$$II.$ $5x + 4y = 40$Multiply equation $(I)$ by $4$ and equation $(II)$ by $3$ to eliminate $y$:$(7x - 3y) 	imes 4 = 13 	imes 4 \Rightarrow 28x - 12y = 52$$(5x + 4y) 	imes 3 = 40 	imes 3 \Rightarrow 15x + 12y = 120$Adding the two resulting equations:$(28x - 12y) + (15x + 12y) = 52 + 120$$43x = 172$$x = 172 / 43 = 4$Substitute $x = 4$ into equation $(I)$:$7(4) - 3y = 13$$28 - 3y = 13$$3y = 28 - 13$$3y = 15$$y = 5$Comparing the values,$x = 4$ and $y = 5$,we find that $x < y$.

Solve the given two equations and select the correct option.
$I.$ $7x - 3y = 13$
$II.$ $5x + 4y = 40$

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Solve the given two equations and select the correct option.$I.$ $7x - 3y = 13$$II.$ $5x + 4y = 40$