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(D) For equation $I$: $2x^2 - 3x - 35 = 0$Using the quadratic formula or factoring: $2x^2 - 10x + 7x - 35 = 0$$2x(x - 5) + 7(x - 5) = 0$$(2x + 7)(x -

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if $x = y$ or the relationship between $x$ and $y$ cannot be established.

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(D) For equation $I$: $2x^2 - 3x - 35 = 0$Using the quadratic formula or factoring: $2x^2 - 10x + 7x - 35 = 0$$2x(x - 5) + 7(x - 5) = 0$$(2x + 7)(x - 5) = 0$So,$x = 5$ or $x = -3.5$.For equation $II$: $y^2 - 7y + 6 = 0$Factoring: $y^2 - 6y - y + 6 = 0$$y(y - 6) - 1(y - 6) = 0$$(y - 1)(y - 6) = 0$So,$y = 1$ or $y = 6$.Comparing the values:If $x = 5$,then $x > y$ (when $y = 1$) and $x Since the relationship changes depending on the values,the relationship between $x$ and $y$ cannot be established.

Solve the given two equations and select the correct answer from the given options.
$I.$ $2x^2 - 3x - 35 = 0$
$II.$ $y^2 - 7y + 6 = 0$

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Solve the given two equations and select the correct answer from the given options.$I.$ $2x^2 - 3x - 35 = 0$$II.$ $y^2 - 7y + 6 = 0$