Solve the given two equations and select the correct option.
$I.$ $x^{2} + 42 = 13x$
$II.$ $y = \sqrt[4]{1296}$
$I.$ $x^{2} + 42 = 13x$
$II.$ $y = \sqrt[4]{1296}$
- Aif $x > y$
- Bif $x \ge y$
- Cif $x < y$
- Dif $x \le y$
Explore More
Similar Questions
If the expression $\left( mx - 1 + \frac{1}{x} \right)$ is always non-negative for $x > 0$,then the minimum value of $m$ must be
Difficult
View SolutionSolve the given two equations and select the correct answer from the given options.
$I.$ $2x^2 + 13x - 7 = 0$
$II.$ $2y^2 - 5y + 3 = 0$
$I.$ $2x^2 + 13x - 7 = 0$
$II.$ $2y^2 - 5y + 3 = 0$
Difficult
View SolutionIf $2 + 3i$ is one of the roots of the equation $2x^3 - 9x^2 + kx - 13 = 0,$ where $k \in R,$ then the real root of this equation
Medium
View SolutionIf the roots of the equation $\frac{x^2 - bx}{ax - c} = \frac{m - 1}{m + 1}$ are equal but opposite in sign,then the value of $m$ is:
Medium
View SolutionIf one root of $ax^2 + bx + c = 0$ is the square of the other,then the value of $b^3 + ac^2 + a^2c$ is
Medium
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo