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(D) For equation $I$: $36 x^{2}+47 \sqrt{7} x+105=0$We factorize the quadratic equation: $36 x^{2}+27 \sqrt{7} x+20 \sqrt{7} x+105=0$$9 x(4 x+3 \sqrt{

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if $x = y$ or the relationship between $x$ and $y$ cannot be established.

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(D) For equation $I$: $36 x^{2}+47 \sqrt{7} x+105=0$We factorize the quadratic equation: $36 x^{2}+27 \sqrt{7} x+20 \sqrt{7} x+105=0$$9 x(4 x+3 \sqrt{7})+5 \sqrt{7}(4 x+3 \sqrt{7})=0$$(9 x+5 \sqrt{7})(4 x+3 \sqrt{7})=0$$x = -\frac{5 \sqrt{7}}{9} \approx -1.47$ and $x = -\frac{3 \sqrt{7}}{4} \approx -1.98$For equation $II$: $35 y^{2}+20 \sqrt{3} y+63 \sqrt{2} y+36 \sqrt{6}=0$$5 y(7 y+4 \sqrt{3})+9 \sqrt{2}(7 y+4 \sqrt{3})=0$$(5 y+9 \sqrt{2})(7 y+4 \sqrt{3})=0$$y = -\frac{9 \sqrt{2}}{5} \approx -2.54$ and $y = -\frac{4 \sqrt{3}}{7} \approx -0.99$Comparing the values:$x_1 = -1.47, x_2 = -1.98$$y_1 = -2.54, y_2 = -0.99$Since $x_1 > y_1$ and $x_1 < y_2$,the relationship between $x$ and $y$ cannot be established.

Solve the given two equations and select the correct option.
$I.$ $36 x^{2}+47 \sqrt{7} x+105=0$
$II.$ $35 y^{2}+20 \sqrt{3} y+63 \sqrt{2} y+36 \sqrt{6}=0$

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Solve the given two equations and select the correct option.$I.$ $36 x^{2}+47 \sqrt{7} x+105=0$$II.$ $35 y^{2}+20 \sqrt{3} y+63 \sqrt{2} y+36 \sqrt{6}=0$