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(D) For equation $I$: $7x^{2} + 16x - 15 = 0$We factorize the quadratic equation: $7x^{2} + 21x - 5x - 15 = 0$$7x(x + 3) - 5(x + 3) = 0$$(7x - 5)(x +

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if $x = y$ or relationship between $x$ and $y$ cannot be established.

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(D) For equation $I$: $7x^{2} + 16x - 15 = 0$We factorize the quadratic equation: $7x^{2} + 21x - 5x - 15 = 0$$7x(x + 3) - 5(x + 3) = 0$$(7x - 5)(x + 3) = 0$So,$x = 5/7 \approx 0.71$ or $x = -3$.For equation $II$: $y^{2} - 6y - 7 = 0$We factorize the quadratic equation: $y^{2} - 7y + y - 7 = 0$$y(y - 7) + 1(y - 7) = 0$$(y + 1)(y - 7) = 0$So,$y = -1$ or $y = 7$.Comparing the values:If $x = 0.71$,then $x > y$ (for $y = -1$) and $x If $x = -3$,then $x Since the relationship changes depending on the values chosen,the relationship between $x$ and $y$ cannot be established.

Solve the given two equations and select the correct answer from the given options.
$I.$ $7x^{2} + 16x - 15 = 0$
$II.$ $y^{2} - 6y - 7 = 0$

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Solve the given two equations and select the correct answer from the given options.$I.$ $7x^{2} + 16x - 15 = 0$$II.$ $y^{2} - 6y - 7 = 0$