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(D) For equation $I$: $3x^2 - 6x - \sqrt{17}x + 2\sqrt{17} = 0$$3x(x - 2) - \sqrt{17}(x - 2) = 0$$(x - 2)(3x - \sqrt{17}) = 0$Thus,$x = 2$ or $x = \fr

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if $x = y$ or relationship between $x$ and $y$ cannot be established.

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(D) For equation $I$: $3x^2 - 6x - \sqrt{17}x + 2\sqrt{17} = 0$$3x(x - 2) - \sqrt{17}(x - 2) = 0$$(x - 2)(3x - \sqrt{17}) = 0$Thus,$x = 2$ or $x = \frac{\sqrt{17}}{3} \approx \frac{4.12}{3} \approx 1.37$.For equation $II$: $5y^2 - 15y + \sqrt{17}y - 3\sqrt{17} = 0$$5y(y - 3) + \sqrt{17}(y - 3) = 0$$(y - 3)(5y + \sqrt{17}) = 0$Thus,$y = 3$ or $y = -\frac{\sqrt{17}}{5} \approx -\frac{4.12}{5} \approx -0.82$.Comparing the values:$x$ values are ${2, 1.37}$ and $y$ values are ${3, -0.82}$.Since $x  y$ for $x=1.37, y=-0.82$,the relationship between $x$ and $y$ cannot be established.

Solve the given two equations and provide the correct answer from the given options.
$I.$ $3x^2 - (6 + \sqrt{17})x + 2\sqrt{17} = 0$
$II.$ $5y^2 - (15 - \sqrt{17})y - 3\sqrt{17} = 0$

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Solve the given two equations and provide the correct answer from the given options.$I.$ $3x^2 - (6 + \sqrt{17})x + 2\sqrt{17} = 0$$II.$ $5y^2 - (15 - \sqrt{17})y - 3\sqrt{17} = 0$