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(B) Step $1$: Solve the first equation $x^{2}-6x=7$.$x^{2}-6x-7=0$$x^{2}-7x+x-7=0$$x(x-7)+1(x-7)=0$$(x+1)(x-7)=0$So,$x = -1$ or $x = 7$.Step $2$: Solv

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If $x > y$

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(B) Step $1$: Solve the first equation $x^{2}-6x=7$.$x^{2}-6x-7=0$$x^{2}-7x+x-7=0$$x(x-7)+1(x-7)=0$$(x+1)(x-7)=0$So,$x = -1$ or $x = 7$.Step $2$: Solve the second equation $2y^{2}+13y+15=0$.$2y^{2}+10y+3y+15=0$$2y(y+5)+3(y+5)=0$$(2y+3)(y+5)=0$So,$y = -1.5$ or $y = -5$.Step $3$: Compare the values.Possible values for $x$ are $\{-1, 7\}$.Possible values for $y$ are $\{-1.5, -5\}$.Comparing the values: Since $-1 > -1.5$,$-1 > -5$,$7 > -1.5$,and $7 > -5$,it is clear that $x > y$ in all cases.

Solve the given two equations and select the correct answer from the given options.
$I.$ $x^{2}-6x=7$
$II.$ $2y^{2}+13y+15=0$

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Solve the given two equations and select the correct answer from the given options.$I.$ $x^{2}-6x=7$$II.$ $2y^{2}+13y+15=0$