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(B) Step $1$: Solve equation $I$ for $x$.$x^{3} - 468 = 1729$$x^{3} = 1729 + 468$$x^{3} = 2197$$x = \sqrt[3]{2197} = 13$Step $2$: Solve equation $II$

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if $x \geq y$

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(B) Step $1$: Solve equation $I$ for $x$.$x^{3} - 468 = 1729$$x^{3} = 1729 + 468$$x^{3} = 2197$$x = \sqrt[3]{2197} = 13$Step $2$: Solve equation $II$ for $y$.$y^{2} - 1733 + 1564 = 0$$y^{2} - 169 = 0$$y^{2} = 169$$y = \pm 13$Step $3$: Compare the values of $x$ and $y$.$x = 13$$y = 13$ or $y = -13$Comparing these,we get $x = 13$ and $y = 13$ (so $x = y$) or $x = 13$ and $y = -13$ (so $x > y$).Combining these results,we conclude $x \geq y$.

Solve the given two equations and select the correct option.
$I.$ $x^{3} - 468 = 1729$
$II.$ $y^{2} - 1733 + 1564 = 0$

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Solve the given two equations and select the correct option.$I.$ $x^{3} - 468 = 1729$$II.$ $y^{2} - 1733 + 1564 = 0$