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(B) Step $1$: Solve equation $I$: $x^{2}-7x+12=0$.Factorizing the quadratic equation: $x^{2}-4x-3x+12=0$.$x(x-4)-3(x-4)=0$.$(x-3)(x-4)=0$.So,$x = 3$ o

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if $x \geq y$

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(B) Step $1$: Solve equation $I$: $x^{2}-7x+12=0$.Factorizing the quadratic equation: $x^{2}-4x-3x+12=0$.$x(x-4)-3(x-4)=0$.$(x-3)(x-4)=0$.So,$x = 3$ or $x = 4$.Step $2$: Solve equation $II$: $y^{2}+y-12=0$.Factorizing the quadratic equation: $y^{2}+4y-3y-12=0$.$y(y+4)-3(y+4)=0$.$(y-3)(y+4)=0$.So,$y = 3$ or $y = -4$.Step $3$: Compare the values of $x$ and $y$:If $x=3$,then $y=3$ $(x=y)$ or $y=-4$ $(x>y)$.If $x=4$,then $y=3$ $(x>y)$ or $y=-4$ $(x>y)$.In all cases,$x$ is either greater than or equal to $y$. Therefore,$x \geq y$.

Solve the given two equations and select the correct answer from the given options.
$I.$ $x^{2}-7x+12=0$
$II.$ $y^{2}+y-12=0$

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Solve the given two equations and select the correct answer from the given options.$I.$ $x^{2}-7x+12=0$$II.$ $y^{2}+y-12=0$