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(C) For equation $I$: $2x^{2} + 11x + 14 = 0$$2x^{2} + 4x + 7x + 14 = 0$$2x(x + 2) + 7(x + 2) = 0$$(2x + 7)(x + 2) = 0$$x = -3.5$ or $x = -2$For equat

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if $x < y$

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(C) For equation $I$: $2x^{2} + 11x + 14 = 0$$2x^{2} + 4x + 7x + 14 = 0$$2x(x + 2) + 7(x + 2) = 0$$(2x + 7)(x + 2) = 0$$x = -3.5$ or $x = -2$For equation $II$: $4y^{2} + 12y + 9 = 0$$(2y)^{2} + 2(2y)(3) + 3^{2} = 0$$(2y + 3)^{2} = 0$$2y = -3$$y = -1.5$Comparing the values:$x_1 = -3.5, x_2 = -2$$y = -1.5$Since $-3.5 < -1.5$ and $-2 < -1.5$,we conclude that $x < y$.

Solve the given two equations and select the correct answer from the given options.
$I.$ $2x^{2} + 11x + 14 = 0$
$II.$ $4y^{2} + 12y + 9 = 0$

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Solve the given two equations and select the correct answer from the given options.$I.$ $2x^{2} + 11x + 14 = 0$$II.$ $4y^{2} + 12y + 9 = 0$