Solve the inequality $2 \leq 3x - 4 \leq 5$.

Solve the given inequality graphically in a two-dimensional plane: $3x + 4y \leq 12$.

Out of the following points,how many points satisfy the inequality $2x - 3y > -5$?
$(1, 1), (-1, 1), (1, -1), (-1, -1), (-2, 1), (2, -1), (-1, 2)$ and $(-2, -1)$

Consider the following statements :
Statement $(I)$ : The set of all solutions of the linear inequalities $3x + 8 < 17$ and $2x + 8 \geq 12$ are $x < 3$ and $x \geq 2$ respectively.
Statement $(II)$ : The common set of solutions of linear inequalities $3x + 8 < 17$ and $2x + 8 \geq 12$ is $(2, 3)$.
Which of the following is true?

Solve the following system of inequalities:
$8x + 3y \leq 100$ $(1)$
$x \geq 0$ $(2)$
$y \geq 0$ $(3)$

The solution set of $x < 5$ and $x \geq 2$ is...