Specify the quantum number for the limit wave | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The wavelength $\lambda$ of a spectral line in the hydrogen atom is given by the Rydberg formula: $\frac{1}{\lambda} = R \left( \frac{1}{n_1^2} -

Vedclass · Accepted Answer

$n_1 = 1, n_2 = \infty$

Vedclass · Answer

(A) The wavelength $\lambda$ of a spectral line in the hydrogen atom is given by the Rydberg formula: $\frac{1}{\lambda} = R \left( \frac{1}{n_1^2} - \frac{1}{n_2^2} \right)$,where $n_1$ is the lower energy level and $n_2$ is the higher energy level.For the limit wavelength (also known as the series limit),the wavelength is at its minimum,which corresponds to the maximum possible energy transition.This occurs when the electron transitions from an infinite energy level $(n_2 = \infty)$ to the specific lower energy level $(n_1)$ of the series.Therefore,for the limit wavelength,the quantum numbers are $n_1$ (fixed for the series) and $n_2 = \infty$.

Specify the quantum number for the limit wavelength of the spectral series of a hydrogen atom.

Similar Questions

If $\lambda_{1}$ and $\lambda_{2}$ are the wavelengths of the third member of the Lyman series and the first member of the Paschen series respectively,then the value of $\lambda_{1} : \lambda_{2}$ is

If $\lambda_1$ is the wavelength of the series limit of the Lyman series,$\lambda_2$ is the wavelength of the first line of the Lyman series,and $\lambda_3$ is the series limit of the Balmer series,then the relation between $\lambda_1, \lambda_2,$ and $\lambda_3$ is:

If ${\lambda _{\max }}$ is $6563\,\mathring{A}$ for the Balmer series of a particular atom,then the wavelength of the second line for the Balmer series will be:

In a hydrogen atom,a transition from the state $n=6$ to $n=1$ results in ultraviolet radiation. Infrared radiation will be obtained in the transition:

$A$ hydrogen atom in the ground state is given an energy of $10.2 \ eV$. How many spectral lines will be emitted due to the transition of electrons?

Vedclass Test Series

Exam Paper Generator

Online Exam Module