The spin-only magnetic moment in BM of [Fe(CO | vedclass

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(D) In the complex $[Fe(CO)_4(C_2O_4)]^+$,let the oxidation state of $Fe$ be $x$.$x + 4(0) + (-2) = +1$$x = +3$$Fe^{3+}$ has a $3d^5$ configuration.$C

Vedclass · Accepted Answer

$1.73$

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(D) In the complex $[Fe(CO)_4(C_2O_4)]^+$,let the oxidation state of $Fe$ be $x$.$x + 4(0) + (-2) = +1$$x = +3$$Fe^{3+}$ has a $3d^5$ configuration.$CO$ is a strong field ligand,and $C_2O_4^{2-}$ (oxalate) is a chelating ligand.In the presence of strong field ligands,the $d$-electrons pair up.For $Fe^{3+}$ $(3d^5)$,the pairing results in one unpaired electron $(n = 1)$.The spin-only magnetic moment is given by $\mu = \sqrt{n(n+2)} \ BM$.$\mu = \sqrt{1(1+2)} \ BM = \sqrt{3} \ BM \approx 1.73 \ BM$.

The spin-only magnetic moment in $BM$ of $[Fe(CO)_4(C_2O_4)]^+$ is:

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