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(D) The 'spin only' magnetic moment $(\mu)$ is calculated using the formula $\mu = \sqrt{n(n+2)} \ BM$,where $n$ is the number of unpaired ele

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$B$ and $D$ only

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(D) The 'spin only' magnetic moment $(\mu)$ is calculated using the formula $\mu = \sqrt{n(n+2)} \ BM$,where $n$ is the number of unpaired electrons.

	
		
			Ion and Configuration
			No. of unpaired electrons $(n)$
		
		
			$Ti^{3+}: 3d^{1}$
			$1$
		
		
			$Cr^{2+}: 3d^{4}$
			$4$
		
		
			$Mn^{2+}: 3d^{5}$
			$5$
		
		
			$Fe^{2+}: 3d^{6}$
			$4$
		
		
			$Sc^{3+}: 3d^{0}$
			$0$
		
	


Since $Cr^{2+}$ and $Fe^{2+}$ both have $n = 4$ unpaired electrons,they have the same 'spin only' magnetic moment.

Column $A$	Column $B$
$(1)$ $V^{4+}$	$(a)$ Colorless
$(2)$ $Ti^{3+}$	$(b)$ Pink
$(3)$ $Ti^{4+}$	$(c)$ Purple
$(4)$ $Mn^{2+}$	$(d)$ Blue
	$(e)$ Violet

'Spin only' magnetic moment is same for which of the following ions?
$A$. $Ti^{3+}$ $B$. $Cr^{2+}$ $C$. $Mn^{2+}$ $D$. $Fe^{2+}$ $E$. $Sc^{3+}$
Choose the most appropriate answer from the options given below.

Similar Questions

Which of the following is a diamagnetic ion?

Which of the following ions has the highest magnetic moment?

Match Column $A$ with Column $B$:

Column $A$ Column $B$

$(1)$ $V^{4+}$ $(a)$ Colorless

$(2)$ $Ti^{3+}$ $(b)$ Pink

$(3)$ $Ti^{4+}$ $(c)$ Purple

$(4)$ $Mn^{2+}$ $(d)$ Blue

$(e)$ Violet

In the $3d$ transition series,as the atomic number increases,the paramagnetic character:

$A$ copper salt is isomorphic with $ZnSO_4$. The salt will be:

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'Spin only' magnetic moment is same for which of the following ions? $A$. $Ti^{3+}$ $B$. $Cr^{2+}$ $C$. $Mn^{2+}$ $D$. $Fe^{2+}$ $E$. $Sc^{3+}$ Choose the most appropriate answer from the options given below.