The spin-only magnetic moment of an octahedra | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The electronic configuration of $Fe^{2+}$ is $[Ar] 3d^6$.In the presence of a strong field ligand $(SFL)$,the crystal field splitting energy $\Del

Vedclass · Accepted Answer

$0$

Vedclass · Answer

(B) The electronic configuration of $Fe^{2+}$ is $[Ar] 3d^6$.In the presence of a strong field ligand $(SFL)$,the crystal field splitting energy $\Delta_0$ is greater than the pairing energy $P$ $(\Delta_0 > P)$.This causes the electrons to pair up in the $t_{2g}$ orbitals.The distribution of electrons in the $t_{2g}$ orbitals is $(t_{2g})^6 (e_g)^0$.Since all electrons are paired,the number of unpaired electrons $(n)$ is $0$.The spin-only magnetic moment $\mu$ is calculated as $\mu = \sqrt{n(n+2)} \ B.M.$Substituting $n = 0$,we get $\mu = \sqrt{0(0+2)} = 0 \ B.M.$

The spin-only magnetic moment of an octahedral complex of $Fe^{2+}$ in the presence of a strong field ligand in $B.M.$ is $.....$

Similar Questions

Which of the following outer octahedral complexes have the same number of unpaired electrons?
$1$. $[MnCl_6]^{3-}$
$2$. $[FeF_6]^{3-}$
$3$. $[CoF_6]^{3-}$
$4$. $[Ni(NH_3)_6]^{2+}$

Which of the following complexes will not show optical isomerism?

Identify the correct pair of properties of the $[Co(NH_3)_6]^{3+}$ complex ion.

The complex that can show $fac-$ and $mer-$isomers is

Vedclass Test Series

Exam Paper Generator

Online Exam Module