(B) The standard reduction potential for the cathode $(Sn^{4+}/Sn^{2+})$ is $E_{cathode}^{0} = +0.15 \ V$. The standard reduction potential for the an

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

(B) The standard reduction potential for the cathode $(Sn^{4+}/Sn^{2+})$ is $E_{cathode}^{0} = +0.15 \ V$. The standard reduction potential for the anode $(Cr^{3+}/Cr)$ is $E_{anode}^{0} = -0.74 \ V$. The standard cell potential is calculated using the formula: $E_{cell}^{0} = E_{cathode}^{0} - E_{anode}^{0}$. Substituting the values: $E_{cell}^{0} = 0.15 \ V - (-0.74 \ V) = 0.15 + 0.74 = +0.89 \ V$.

Class 12 Chemistry Electrochemistry Electrode potential and ECell

Difficult

Standard electrode potential for $Sn^{4+}/Sn^{2+}$ couple is $+0.15 \ V$ and that for the $Cr^{3+}/Cr$ couple is $-0.74 \ V.$ These two couples in their standard state are connected to make a cell. The cell potential will be ........ $V$

AIPMT 2011 All AIPMT

A
$+1.19$
B
$+0.89$
C
$+0.18$
D
$+1.83$

Explore More

Browse All

Question Bank

All Subjects

Class 12 Questions

Class 12

Chemistry Questions

Chapter

Electrochemistry

Subtopic

Electrode potential and ECell

Previous Year

AIPMT 2011 Paper All AIPMT years →

$E^{\circ}$ of $Cu$ is $+0.34 \ V$ while that of $Zn$ is $-0.76 \ V$. Explain.

Medium

View Solution

What will be the $EMF$ of the cell formed by the following half-cells in $V$?
$Mg^{2+} + 2e^- \to Mg_{(s)}; E = -2.37 \ V$
$Cu^{2+} + 2e^- \to Cu_{(s)}; E = +0.33 \ V$

Easy

View Solution

Electrode potentials of five elements $A, B, C, D$ and $E$ are respectively $-1.36 \ V, -0.32 \ V, 0 \ V, -1.26 \ V$ and $-0.42 \ V$. The reactivity order of these elements is:

Medium

View Solution

When does a cell reaction occur spontaneously?

Easy

View Solution

Calculate $E^o_{cell}$ for the following cell in $V$:
$Zn_{(s)} | Zn^{2+}_{(aq.)} || Ag^{+}_{(aq.)} | Ag_{(s)}$
Given: $E^o_{Zn^{2+}/Zn} = -0.76 \ V$ ; $E^o_{Ag^{+}/Ag} = 0.80 \ V$

Easy

View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial

For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free

For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo

Standard electrode potential for $Sn^{4+}/Sn^{2+}$ couple is $+0.15 \ V$ and that for the $Cr^{3+}/Cr$ couple is $-0.74 \ V.$ These two couples in their standard state are connected to make a cell. The cell potential will be ........ $V$

Similar Questions

$E^{\circ}$ of $Cu$ is $+0.34 \ V$ while that of $Zn$ is $-0.76 \ V$. Explain.

What will be the $EMF$ of the cell formed by the following half-cells in $V$?$Mg^{2+} + 2e^- \to Mg_{(s)}; E = -2.37 \ V$$Cu^{2+} + 2e^- \to Cu_{(s)}; E = +0.33 \ V$

Electrode potentials of five elements $A, B, C, D$ and $E$ are respectively $-1.36 \ V, -0.32 \ V, 0 \ V, -1.26 \ V$ and $-0.42 \ V$. The reactivity order of these elements is:

When does a cell reaction occur spontaneously?

Calculate $E^o_{cell}$ for the following cell in $V$:$Zn_{(s)} | Zn^{2+}_{(aq.)} || Ag^{+}_{(aq.)} | Ag_{(s)}$Given: $E^o_{Zn^{2+}/Zn} = -0.76 \ V$ ; $E^o_{Ag^{+}/Ag} = 0.80 \ V$

Vedclass Test Series

Exam Paper Generator

Online Exam Module

What will be the $EMF$ of the cell formed by the following half-cells in $V$?
$Mg^{2+} + 2e^- \to Mg_{(s)}; E = -2.37 \ V$
$Cu^{2+} + 2e^- \to Cu_{(s)}; E = +0.33 \ V$

Calculate $E^o_{cell}$ for the following cell in $V$:
$Zn_{(s)} | Zn^{2+}_{(aq.)} || Ag^{+}_{(aq.)} | Ag_{(s)}$
Given: $E^o_{Zn^{2+}/Zn} = -0.76 \ V$ ; $E^o_{Ag^{+}/Ag} = 0.80 \ V$