Standard reduction potentials at 25^circ C of | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The strength of an oxidizing agent is directly proportional to its standard reduction potential $(E^\circ_{red})$.Higher reduction potential indic

Vedclass · Accepted Answer

$Mg^{2+}$

Vedclass · Answer

(D) The strength of an oxidizing agent is directly proportional to its standard reduction potential $(E^\circ_{red})$.Higher reduction potential indicates a greater tendency to gain electrons,making the species a stronger oxidizing agent.Comparing the given values: $E^\circ(Li^{+}|Li) = -3.05 \ V$,$E^\circ(Ba^{2+}|Ba) = -2.90 \ V$,$E^\circ(Na^{+}|Na) = -2.71 \ V$,and $E^\circ(Mg^{2+}|Mg) = -2.37 \ V$.Since $-2.37 \ V$ is the highest value among the given potentials,$Mg^{2+}$ is the strongest oxidizing agent.

Standard reduction potentials at $25^\circ C$ of $Li^{+}|Li$,$Ba^{2+}|Ba$,$Na^{+}|Na$,and $Mg^{2+}|Mg$ are $-3.05 \ V$,$-2.90 \ V$,$-2.71 \ V$,and $-2.37 \ V$ respectively. Which one of the following is the strongest oxidising agent?

Similar Questions

What is the value of the standard electrode potential of a standard hydrogen electrode $(SHE)$ (in $V$)?

$Cr_2O_7^{2-} + I^{-} \to I_2 + Cr^{3+}$
$E^0_{cell} = 0.79 \ V$
$E^0_{Cr_2O_7^{2-}} = 1.33 \ V$,$E^0_{I_2}$ is ........... $V$

Which of the following has been universally accepted as a reference electrode at all temperatures and has been assigned a value of zero volt?

$Mg^{2+}$ displaces hydrogen from acids but copper does not. $A$ galvanic cell prepared by combining $Cu/Cu^{2+}$ and $Mg/Mg^{2+}$ has an $EMF$ of $2.71 \ V$ at $298 \ K$. If the potential of copper electrode is $0.34 \ V$,what is the reduction potential of $Mg$ electrode?

Which of the following metals cannot displace $H_2$ from acids or $H_2O$ from its compounds?

Vedclass Test Series

Exam Paper Generator

Online Exam Module