(A) Part $1$: Acceleration phaseInitial velocity $u = 0 \, m/s$,Final velocity $v = 36 \, km/h = 36 \times (5/18) = 10 \, m/s$,Time $t_1 = 10 \, s$.Ac

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Acceleration = $1 \, m/s^2$,Deceleration = $-0.5 \, m/s^2$,Distance = $150 \, m$

(A) Part $1$: Acceleration phaseInitial velocity $u = 0 \, m/s$,Final velocity $v = 36 \, km/h = 36 \times (5/18) = 10 \, m/s$,Time $t_1 = 10 \, s$.Acceleration $a_1 = (v - u) / t_1 = (10 - 0) / 10 = 1 \, m/s^2$.Distance $s_1 = ut_1 + 0.5 a_1 t_1^2 = 0 + 0.5 \times 1 \times 10^2 = 50 \, m$.Part $2$: Deceleration phaseInitial velocity $u = 10 \, m/s$,Final velocity $v = 0 \, m/s$,Time $t_2 = 20 \, s$.Acceleration $a_2 = (v - u) / t_2 = (0 - 10) / 20 = -0.5 \, m/s^2$.Distance $s_2 = ut_2 + 0.5 a_2 t_2^2 = 10 \times 20 + 0.5 \times (-0.5) \times 20^2 = 200 - 100 = 100 \, m$.Total distance = $s_1 + s_2 = 50 + 100 = 150 \, m$.

Class 9 Science MOTION Mix Examples - MOTION

Medium

Starting from rest,a scooter acquires a velocity of $36 \, km/h$ in $10 \, s$ and then brakes are applied,taking $20 \, s$ to stop. Calculate the acceleration and the total distance travelled.

A
Acceleration = $1 \, m/s^2$,Deceleration = $-0.5 \, m/s^2$,Distance = $150 \, m$
B
Acceleration = $1 \, m/s^2$,Deceleration = $-0.5 \, m/s^2$,Distance = $200 \, m$
C
Acceleration = $1 \, m/s^2$,Deceleration = $-0.5 \, m/s^2$,Distance = $250 \, m$
D
Acceleration = $1 \, m/s^2$,Deceleration = $-0.5 \, m/s^2$,Distance = $300 \, m$

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$A$ car travels $100\, km$ east and then $100\, km$ south. Finally,it comes back to the starting point by the south-east route. Throughout the journey the speed is constant at $60\, km\, h^{-1}$. The average velocity for the whole journey if the time taken is $3.3\, h$ is

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There is an argument about uniform acceleration between $Mr. X$ and $Mr. Y$. $Mr. X$ says,"acceleration means that the farther you go, the faster you go". $Mr. Y$ says,"acceleration means that the longer you go, the faster you go". Whose statement is correct?

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Out of the three speed-time graphs shown below,identify the graph for the following cases:
$(i)$ $A$ ball thrown vertically upwards and returning to the hand of the thrower.
(ii) $A$ body decelerating to a constant speed and then accelerating.

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The speed-time graphs of two cars are represented by $P$ and $Q$ as shown below.
$(a)$ Find the difference in the distance travelled by the two cars (in $m$) after $4\, s$.
$(b)$ Do they ever move with the same speed? If so,when?
$(c)$ What type of motion are car $P$ and car $Q$ undergoing?

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The following table shows the position of three persons between $8.00\, am$ to $8.20\, am$.
Time Position of Person $A$ $(km)$ Position of Person $B$ $(km)$ Position of Person $C$ $(km)$
$8.00\, am$ $0$ $0$ $0$
$8.05\, am$ $4$ $5$ $10$
$8.10\, am$ $13$ $10$ $19$
$8.15\, am$ $20$ $15$ $24$
$8.20\, am$ $25$ $20$ $27$

$(i)$ Who is moving with constant speed?
$(ii)$ Who has travelled the maximum distance between $8.00\, am$ to $8.05\, am$?
$(iii)$ Calculate the average speed of person $A$ in $km\, h^{-1}$.

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Time	Position of Person $A$ $(km)$	Position of Person $B$ $(km)$	Position of Person $C$ $(km)$
$8.00\, am$	$0$	$0$	$0$
$8.05\, am$	$4$	$5$	$10$
$8.10\, am$	$13$	$10$	$19$
$8.15\, am$	$20$	$15$	$24$
$8.20\, am$	$25$	$20$	$27$

Starting from rest,a scooter acquires a velocity of $36 \, km/h$ in $10 \, s$ and then brakes are applied,taking $20 \, s$ to stop. Calculate the acceleration and the total distance travelled.

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$A$ car travels $100\, km$ east and then $100\, km$ south. Finally,it comes back to the starting point by the south-east route. Throughout the journey the speed is constant at $60\, km\, h^{-1}$. The average velocity for the whole journey if the time taken is $3.3\, h$ is

There is an argument about uniform acceleration between $Mr. X$ and $Mr. Y$. $Mr. X$ says,"acceleration means that the farther you go, the faster you go". $Mr. Y$ says,"acceleration means that the longer you go, the faster you go". Whose statement is correct?

Out of the three speed-time graphs shown below,identify the graph for the following cases:$(i)$ $A$ ball thrown vertically upwards and returning to the hand of the thrower.(ii) $A$ body decelerating to a constant speed and then accelerating.

The speed-time graphs of two cars are represented by $P$ and $Q$ as shown below.$(a)$ Find the difference in the distance travelled by the two cars (in $m$) after $4\, s$.$(b)$ Do they ever move with the same speed? If so,when?$(c)$ What type of motion are car $P$ and car $Q$ undergoing?

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Out of the three speed-time graphs shown below,identify the graph for the following cases:
$(i)$ $A$ ball thrown vertically upwards and returning to the hand of the thrower.
(ii) $A$ body decelerating to a constant speed and then accelerating.

The speed-time graphs of two cars are represented by $P$ and $Q$ as shown below.
$(a)$ Find the difference in the distance travelled by the two cars (in $m$) after $4\, s$.
$(b)$ Do they ever move with the same speed? If so,when?
$(c)$ What type of motion are car $P$ and car $Q$ undergoing?