Starting with three different amino acid mole | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Let the three different amino acids be $A$,$B$,and $C$.For a tripeptide formed by three different amino acids,the number of possible arrangements

Vedclass · Accepted Answer

$6$

Vedclass · Answer

(D) Let the three different amino acids be $A$,$B$,and $C$.For a tripeptide formed by three different amino acids,the number of possible arrangements is given by the permutation of $3$ distinct items taken $3$ at a time.The number of arrangements is $3! = 3 	imes 2 	imes 1 = 6$.The possible tripeptides are: $ABC$,$ACB$,$BAC$,$BCA$,$CAB$,and $CBA$.Thus,$6$ different tripeptide molecules are formed.

$(A)$. Serine	$(B)$. Cysteine
$(C)$. Lysine	$(D)$. Methionine

Starting with three different amino acid molecules,how many different tripeptide molecules are formed?

Similar Questions

The general formula of an $\alpha$-amino acid is shown below. Identify the side chain $-R$ for the amino acid serine.

In the given reaction: $CH_3-CHCl-COOH \xrightarrow[(ii) H_2O]{(i) NH_3 (1 \text{ mole})} [X]$. Product $[X]$ will be:

Which of the following amino acids is basic in nature?

Thiol group is present in:

Which of the following are sulphur-containing amino acids?
$(A)$. Serine $(B)$. Cysteine
$(C)$. Lysine $(D)$. Methionine

Vedclass Test Series

Exam Paper Generator

Online Exam Module