State whether the following statements are True or False:
$(1)$ The metal and non-metal elements of $d$-block react with hydrogen to give molecular hydrides.
$(2)$ At normal temperature,dihydrogen reacts violently with dioxygen.
$(1)$ The metal and non-metal elements of $d$-block react with hydrogen to give molecular hydrides.
$(2)$ At normal temperature,dihydrogen reacts violently with dioxygen.
(A) $(1)$ False. $d$-block elements form interstitial (or metallic) hydrides,not molecular hydrides. Molecular hydrides are typically formed by $p$-block elements.
$(2)$ False. Dihydrogen does not react with dioxygen at normal temperature because the $H-H$ bond dissociation energy is very high. The reaction requires a catalyst,heating,or an electric spark to proceed.
$(2)$ False. Dihydrogen does not react with dioxygen at normal temperature because the $H-H$ bond dissociation energy is very high. The reaction requires a catalyst,heating,or an electric spark to proceed.
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Which of the following ions are present in the anhydrous mixture of $KF$ and $HF$?
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View SolutionIf the boiling point of $H_{2}O$ is $373\,K$,the boiling point of $H_{2}S$ will be:
What do you understand by $(i)$ electron deficient,$(ii)$ electron precise,and $(iii)$ electron rich compounds of hydrogen? Provide justification with suitable examples.
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View SolutionThe correct statements among $(a)$ to $(d)$ are:
$(a)$ Saline hydrides produce $H_2$ gas when reacted with $H_2O$.
$(b)$ Reaction of $LiAlH_4$ with $BF_3$ leads to $B_2H_6$.
$(c)$ $PH_3$ and $CH_4$ are electron-rich and electron-precise hydrides,respectively.
$(d)$ $HF$ and $CH_4$ are called as molecular hydrides.
$(a)$ Saline hydrides produce $H_2$ gas when reacted with $H_2O$.
$(b)$ Reaction of $LiAlH_4$ with $BF_3$ leads to $B_2H_6$.
$(c)$ $PH_3$ and $CH_4$ are electron-rich and electron-precise hydrides,respectively.
$(d)$ $HF$ and $CH_4$ are called as molecular hydrides.
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