State True or False for the following statements:
$(i)$ $\mathop{C}\limits^{+}H_3$ and $CH_3\mathop{C}\limits^{+}H_2$ both are primary carbocations.
$(ii)$ $(CH_3)_3\mathop{C}\limits^{+}$ is a tertiary carbocation and all carbons are $sp^3$ hybridized.
$(iii)$ $\mathop{C}\limits^{+}H_3$ is trigonal planar.
$(iv)$ $CH_4$ is not trigonal planar.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) $(i)$ False. $\mathop{C}\limits^{+}H_3$ (methyl carbocation) is not classified as primary,secondary,or tertiary because it is not attached to any alkyl group. $CH_3\mathop{C}\limits^{+}H_2$ is a primary carbocation.
$(ii)$ False. $(CH_3)_3\mathop{C}\limits^{+}$ is a tertiary carbocation,but the positively charged carbon is $sp^2$ hybridized,not $sp^3$.
$(iii)$ True. The methyl carbocation $\mathop{C}\limits^{+}H_3$ has three bonding pairs and no lone pairs on the central carbon,resulting in $sp^2$ hybridization and a trigonal planar geometry.
$(iv)$ True. $CH_4$ (methane) has four bonding pairs and no lone pairs,resulting in $sp^3$ hybridization and a tetrahedral geometry,not trigonal planar.

Explore More

Similar Questions

Which of the following carbocations will undergo rearrangement?

Which one of the following is an electrophilic intermediate in the reaction of benzene with $CH_3Cl$ in the presence of anhydrous $AlCl_3$?

The correct order of stability is:

In which of the following pairs is $A$ more stable than $B$?
$A$ $B$

Arrange the carbanions,$(CH_3)_3\overline{C}$,$\overline{C}Cl_3$,$(CH_3)_2\overline{C}H$,$C_6H_5\overline{C}H_2$ in order of their decreasing stability:

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo