State whether the quadratic equation $3 x^{2}-4 x+1=0$ has two distinct real roots. Justify your answer.

(A) The given quadratic equation is $3 x^{2}-4 x+1=0$.
Comparing this with the standard form $a x^{2}+b x+c=0$,we get:
$a=3, b=-4, c=1$.
The discriminant $D$ is given by the formula $D = b^{2}-4ac$.
Substituting the values,we get:
$D = (-4)^{2} - 4(3)(1)$
$D = 16 - 12$
$D = 4$.
Since $D > 0$,the quadratic equation has two distinct real roots.