Statement $I$. Despite having an aldehyde group,glucose does not give the Schiff test.
Statement $II$. Glucose exists in $\alpha$ and $\beta$ crystalline forms.
Statement $II$. Glucose exists in $\alpha$ and $\beta$ crystalline forms.
- ABoth statements $I$ and $II$ are incorrect.
- BBoth statements $I$ and $II$ are correct.
- CStatement $I$ is correct but statement $II$ is incorrect.
- DStatement $I$ is incorrect but statement $II$ is correct.
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Similar Questions
Which one of the following is the reagent used to identify glucose?
Easy
View SolutionAssertion : Treatment of $D$-glucose with dilute alkali affords an equilibrium mixture consisting of $D$-mannose,$D$-fructose and starting substance $D$-glucose.
Reason : The reaction involves an intermediate in which hybridization of $C_2$ changes from $sp^3$ to $sp^2$.
Reason : The reaction involves an intermediate in which hybridization of $C_2$ changes from $sp^3$ to $sp^2$.
DifficultAIIMS 2013
View SolutionConsidering the facts that
$I$. sucrose forms glycosidic linkage between $C_1$ of glucose and $C_2$ of fructose,while
$II$. lactose forms glycosidic linkage between $C_1$ of galactose and $C_4$ of glucose.
Choose the correct statement.
$I$. sucrose forms glycosidic linkage between $C_1$ of glucose and $C_2$ of fructose,while
$II$. lactose forms glycosidic linkage between $C_1$ of galactose and $C_4$ of glucose.
Choose the correct statement.
The correct statement$(s)$ about the following sugars $X$ and $Y$ is(are):
$(A)$ $X$ is a reducing sugar and $Y$ is a non-reducing sugar
$(B)$ $X$ is a non-reducing sugar and $Y$ is a reducing sugar
$(C)$ The glycosidic linkages in $X$ and $Y$ are $\alpha$ and $\beta$,respectively
$(D)$ The glycosidic linkages in $X$ and $Y$ are $\beta$ and $\alpha$,respectively
$(A)$ $X$ is a reducing sugar and $Y$ is a non-reducing sugar
$(B)$ $X$ is a non-reducing sugar and $Y$ is a reducing sugar
$(C)$ The glycosidic linkages in $X$ and $Y$ are $\alpha$ and $\beta$,respectively
$(D)$ The glycosidic linkages in $X$ and $Y$ are $\beta$ and $\alpha$,respectively
DifficultIIT 2009
View SolutionGalactose is converted into glucose in
Easy
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