Statement I: Boron does not exhibit allotropy | vedclass

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(D) Boron exhibits allotropy and exists in several crystalline forms such as $\alpha-$rhombohedral,$\beta-$rhombohedral,and $\beta-$tetragonal,as well

Vedclass · Accepted Answer

$I$ is not correct but $II$ is correct

Vedclass · Answer

(D) Boron exhibits allotropy and exists in several crystalline forms such as $\alpha-$rhombohedral,$\beta-$rhombohedral,and $\beta-$tetragonal,as well as an amorphous form. Therefore,Statement $I$ is incorrect. Boron is an extremely hard,black-coloured solid with a very high melting point due to its strong covalent crystal lattice structure. Therefore,Statement $II$ is correct.

Statement $I$: Boron does not exhibit allotropy.
Statement $II$: Boron is an extremely hard and black-coloured solid.

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Statement $I$: Boron does not exhibit allotropy. Statement $II$: Boron is an extremely hard and black-coloured solid.