Statement (A): Among the oxides of nitrogen, | vedclass

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(D) Statement $(A)$: $NO$ has $11$ valence electrons (odd number), making it paramagnetic. $NO_2$ has $17$ valence electrons (odd number), making it p

Vedclass · Accepted Answer

Both $(A)$ and $(B)$ are correct

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(D) Statement $(A)$: $NO$ has $11$ valence electrons (odd number), making it paramagnetic. $NO_2$ has $17$ valence electrons (odd number), making it paramagnetic. Thus, statement $(A)$ is correct.Statement $(B)$: In the gaseous state, $NO$ exists as a monomer with an unpaired electron, making it paramagnetic. In the liquid and solid states, $NO$ dimerizes to form $N_2O_2$, where all electrons are paired, making it diamagnetic. Thus, statement $(B)$ is correct.Therefore, both statements are correct, and option $(D)$ is the correct answer.

Statement $(A)$: Among the oxides of nitrogen, $NO$ and $NO_2$ are paramagnetic.
Statement $(B)$: $NO$ is paramagnetic in the gaseous state and diamagnetic in the liquid state.
The correct answer is:

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Statement $(A)$: Among the oxides of nitrogen, $NO$ and $NO_2$ are paramagnetic.Statement $(B)$: $NO$ is paramagnetic in the gaseous state and diamagnetic in the liquid state.The correct answer is: