Statement (A) Sulphur vapour is paramagnetic. | vedclass

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Question

(A) Statement $(A)$ is correct because sulphur vapour exists as $S_2$ at high temperatures, which is paramagnetic due to the presence of two unpaired

Vedclass · Accepted Answer

Statement $(A)$ is correct, but $(B)$ is wrong.

Vedclass · Answer

(A) Statement $(A)$ is correct because sulphur vapour exists as $S_2$ at high temperatures, which is paramagnetic due to the presence of two unpaired electrons in its antibonding molecular orbitals, similar to $O_2$.Statement $(B)$ is incorrect because the reaction of dilute $HCl$ with iron produces $FeCl_2$ and $H_2$ gas, not $FeCl_3$.The reaction is: $Fe(s) + 2HCl(dil.) \longrightarrow FeCl_2(aq) + H_2(g)$.The $H_2$ gas produced acts as a reducing agent and prevents the oxidation of $Fe^{2+}$ to $Fe^{3+}$.Therefore, statement $(A)$ is correct and statement $(B)$ is wrong.

Statement $(A)$ Sulphur vapour is paramagnetic. Statement $(B)$ Reaction of dil. $HCl$ with finely divided iron forms $FeCl_3$ and $H_2$ gas. The correct answer is

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