Study the following circuit and answer the following questions:
$(i)$ State the type of combination of the two resistors in the circuit.
$(ii)$ How much current would flow through:
$(a)$ $10 \, \Omega$ resistor and
$(b)$ $15 \, \Omega$ resistor?
$(iii)$ What would be the ammeter reading?

(N/A) $(i)$ The two resistors are connected in a parallel combination because both ends of the resistors are connected to the same two points in the circuit.
$(ii)$ According to Ohm's law,$I = \frac{V}{R}$. Since the resistors are in parallel,the potential difference $(V)$ across each resistor is $3 \, V$.
$(a)$ Current through the $10 \, \Omega$ resistor: $I_1 = \frac{V}{R_1} = \frac{3 \, V}{10 \, \Omega} = 0.3 \, A$.
$(b)$ Current through the $15 \, \Omega$ resistor: $I_2 = \frac{V}{R_2} = \frac{3 \, V}{15 \, \Omega} = 0.2 \, A$.
$(iii)$ The ammeter measures the total current $(I)$ flowing through the circuit,which is the sum of the currents through the individual branches:
$I = I_1 + I_2 = 0.3 \, A + 0.2 \, A = 0.5 \, A$.
Therefore,the ammeter reading is $0.5 \, A$.