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(D) Total number of marbles $= 4 + 5 + 3 = 12$.Number of ways to draw $2$ marbles out of $12$ is given by $n(S) = {}^{12}C_2 = \frac{12 	imes 11}{2 \

Vedclass · Accepted Answer

None of these

Vedclass · Answer

(D) Total number of marbles $= 4 + 5 + 3 = 12$.Number of ways to draw $2$ marbles out of $12$ is given by $n(S) = {}^{12}C_2 = \frac{12 	imes 11}{2 	imes 1} = 66$.Number of ways to draw $2$ red marbles out of $4$ red marbles is given by $n(E) = {}^{4}C_2 = \frac{4 	imes 3}{2 	imes 1} = 6$.The probability of drawing $2$ red marbles is $P(E) = \frac{n(E)}{n(S)} = \frac{6}{66} = \frac{1}{11}$.Since $\frac{1}{11}$ is not among the given options,the correct answer is 'None of these'.

Study the given information carefully and answer the questions that follow: $A$ basket contains $4$ red,$5$ blue and $3$ green marbles. If $2$ marbles are drawn at random,what is the probability that both are red?

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