For the given reaction,find the sum of x + y | vedclass

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(B) The reaction involves the conversion of a ketone $(CH_3-CH_2-CO-CH_3)$ into an alkyne $(CH_3-C \equiv C-CH_3)$.Step $1$: Reaction with $PCl_5$ $(x

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$3$

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(B) The reaction involves the conversion of a ketone $(CH_3-CH_2-CO-CH_3)$ into an alkyne $(CH_3-C \equiv C-CH_3)$.Step $1$: Reaction with $PCl_5$ $(x \ mol)$: The ketone reacts with $PCl_5$ to form a gem-dichloride. Since $1 \ mol$ of ketone reacts with $1 \ mol$ of $PCl_5$,$x = 1$.$CH_3-CH_2-CO-CH_3 + PCl_5 \rightarrow CH_3-CH_2-CCl_2-CH_3 + POCl_3$Step $2$: Reaction with $NaNH_2$ $(y \ mol)$: The gem-dichloride undergoes dehydrohalogenation to form an alkyne. This requires $2 \ mol$ of $NaNH_2$ to remove $2 \ mol$ of $HCl$ to form the triple bond. Thus,$y = 2$.$CH_3-CH_2-CCl_2-CH_3 + 2NaNH_2 \rightarrow CH_3-C \equiv C-CH_3 + 2NaCl + 2NH_3$Therefore,$x + y = 1 + 2 = 3$.

For the given reaction,find the sum of $x + y = ?$
$CH_3-CH_2-CO-CH_3 \xrightarrow[(ii) \ y \ mol \ NaNH_2]{(i) \ x \ mol \ PCl_5} CH_3-C \equiv C-CH_3$

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For the given reaction,find the sum of $x + y = ?$$CH_3-CH_2-CO-CH_3 \xrightarrow[(ii) \ y \ mol \ NaNH_2]{(i) \ x \ mol \ PCl_5} CH_3-C \equiv C-CH_3$