Suppose the following reaction sequence: CH e | vedclass

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(A) $1$. $CH \equiv CH + NaNH_2 \rightarrow CH \equiv C^- Na^+ (A)$.$2$. $CH \equiv C^- Na^+ + 2 CH_3 - I \rightarrow CH_3 - C \equiv C - CH_3 (B)$ (B

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Geometrical isomer

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(A) $1$. $CH \equiv CH + NaNH_2 ightarrow CH \equiv C^- Na^+ (A)$.$2$. $CH \equiv C^- Na^+ + 2 CH_3 - I ightarrow CH_3 - C \equiv C - CH_3 (B)$ (But$-2-$yne).$3$. $CH_3 - C \equiv C - CH_3 + H_2 / Pd - BaSO_4 ightarrow 	ext{cis-but-2-ene} (C)$.$4$. The reaction $C \xrightarrow{H_2 / Pd - BaSO_4} \dots$ is redundant or implies further reduction,but the final step $NaNH_2 / 	ext{liq. } NH_3$ is typically used for dehydrohalogenation. Assuming the sequence leads to different isomers of butene or related structures,$C$ (cis-but$-2-$ene) and $D$ (trans-but$-2-$ene) are geometrical isomers.

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