The surface tension of a soap solution is 2 t | vedclass

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Question

(A) soap bubble has two surfaces (inner and outer),so the total change in surface area is $2 	imes (4\pi R^2) = 8\pi R^2$.The work done $W$ is given

Vedclass · Accepted Answer

$64\pi 	imes 10^{-6} \ J$

Vedclass · Answer

(A) soap bubble has two surfaces (inner and outer),so the total change in surface area is $2 	imes (4\pi R^2) = 8\pi R^2$.The work done $W$ is given by the product of surface tension $T$ and the change in surface area $\Delta A$:$W = T 	imes \Delta A = T 	imes 8\pi R^2$.Given:$T = 2 	imes 10^{-2} \ N/m$$R = 2 \ cm = 2 	imes 10^{-2} \ m$Substituting the values:$W = 2 	imes 10^{-2} 	imes 8\pi 	imes (2 	imes 10^{-2})^2$$W = 16\pi 	imes 10^{-2} 	imes 4 	imes 10^{-4}$$W = 64\pi 	imes 10^{-6} \ J$.

The surface tension of a soap solution is $2 \times 10^{-2} \ N/m$. The work done in producing a soap bubble of radius $2 \ cm$ is:

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