Taking the wavelength of the first Balmer line in the hydrogen spectrum ($n = 3$ to $n = 2$) as $660\,nm$,the wavelength of the $2^{nd}$ Balmer line ($n = 4$ to $n = 2$) will be....$nm$.

  • A
    $889.2$
  • B
    $642.7$
  • C
    $488.9$
  • D
    $388.9$

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