The IUPAC name of the compound CH_2 = CH - CH | vedclass

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(B) To determine the $IUPAC$ name,first identify the longest carbon chain containing the double bond. The chain $CH_2 = CH - CH(CH_3) - CH_3$ has $4$

Vedclass · Accepted Answer

$3-$Methylbut$-1-$ene

Vedclass · Answer

(B) To determine the $IUPAC$ name,first identify the longest carbon chain containing the double bond. The chain $CH_2 = CH - CH(CH_3) - CH_3$ has $4$ carbon atoms,so the parent alkane is butane. Numbering the chain from the end closer to the double bond gives the double bond position at $C-1$. The methyl group is attached at the $C-3$ position. Therefore,the correct name is $3-$methylbut$-1-$ene.

The $IUPAC$ name of the compound $CH_2 = CH - CH(CH_3)_2$ is

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