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(B) From the graph,for forward bias:Forward bias resistance $R_f = \frac{\Delta V}{\Delta I} = \frac{0.8 - 0.7}{(20 - 10) 	imes 10^{-3} 	ext{ A}} =

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$10^{-6}$

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(B) From the graph,for forward bias:Forward bias resistance $R_f = \frac{\Delta V}{\Delta I} = \frac{0.8 - 0.7}{(20 - 10) 	imes 10^{-3} 	ext{ A}} = \frac{0.1}{10 	imes 10^{-3}} = \frac{0.1}{0.01} = 10 \, \Omega$.For reverse bias:Reverse bias resistance $R_r = \frac{V}{I} = \frac{10 	ext{ V}}{1 	imes 10^{-6} 	ext{ A}} = 10^7 \, \Omega$.The ratio of forward to reverse bias resistance is $\frac{R_f}{R_r} = \frac{10}{10^7} = 10^{-6}$.

The $V-I$ characteristic of a diode is shown in the figure. The ratio of forward to reverse bias resistance is

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