(C) The atomic number of element $X$ is $71$. The electronic configuration of this element (Lutetium) is $[Xe]4f^{14} 5d^1 6s^2$. According to the Auf

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(C) The atomic number of element $X$ is $71$. The electronic configuration of this element (Lutetium) is $[Xe]4f^{14} 5d^1 6s^2$. According to the Aufbau principle,the electrons fill orbitals in increasing order of energy. For $Z = 71$,the configuration is $1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^{10} 4p^6 5s^2 4d^{10} 5p^6 6s^2 4f^{14} 5d^1$. The last electron ($71^{st}$ electron) enters the $5d$ orbital.

Class 11 Chemistry Structure of Atom Quantum number, Electronic configuration and Shape of orbitals

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The $71^{st}$ electron of an element $X$ with an atomic number of $71$ enters into the orbital:

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A
$6p$
B
$4f$
C
$5d$
D
$6s$

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Structure of Atom

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Quantum number, Electronic configuration and Shape of orbitals

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Using $s$,$p$,$d$,and $f$ notations,describe the orbital with the following quantum numbers:
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Explain the meaning of the $+ve$ and $-ve$ signs in the context of the wave function $\psi$ for an electron.

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The $71^{st}$ electron of an element $X$ with an atomic number of $71$ enters into the orbital:

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Using $s$,$p$,$d$,and $f$ notations,describe the orbital with the following quantum numbers:
$(a)$ $n=1$,$l=0$
$(b)$ $n=3$,$l=1$
$(c)$ $n=4$,$l=2$
$(d)$ $n=4$,$l=3$