The IUPAC name of the following compound is | vedclass

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(D) $1$. Identify the principal functional group: The carboxylic acid group $(-COOH)$ has the highest priority and is attached to the ring,so the pare

Vedclass · Accepted Answer

$5-$cyano$-3-$hydroxycyclohex$-2-$enecarboxylic acid

Vedclass · Answer

(D) $1$. Identify the principal functional group: The carboxylic acid group $(-COOH)$ has the highest priority and is attached to the ring,so the parent name will end in $cyclohexanecarboxylic$ $acid$.$2$. Number the ring: Start numbering from the carbon atom attached to the $-COOH$ group as $C-1$. To give the lowest possible locants to the double bond,hydroxyl group,and cyano group,we number the ring in a counter-clockwise direction.$3$. Assign locants: The double bond starts at $C-2$,the hydroxyl group $(-OH)$ is at $C-3$,and the cyano group $(-CN)$ is at $C-5$.$4$. Assemble the name: The substituents are $5-$cyano and $3-$hydroxy. The double bond is at position $2$. Combining these,we get $5-$cyano$-3-$hydroxycyclohex$-2-$enecarboxylic acid.

The $IUPAC$ name of the following compound is

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