The $x-t$ equation is given as $x = 2t + 1$. The corresponding $v-t$ graph is:

The position of an object moving along the $x$-axis is given by $x = a + b t^{2}$,where $a = 8.5 \; m$,$b = 2.5 \; m s^{-2}$,and $t$ is measured in seconds. What is the velocity at $t = 0 \; s$ and $t = 2.0 \; s$?

The relation $3t = \sqrt{3x} + 6$ describes the displacement of a particle in one direction,where $x$ is in $m$ and $t$ is in $s$. The displacement,when velocity is zero,is ......... $m$.

From the given $v-t$ graph,find the ratio of distance to displacement in $25\,s$ of motion.

Draw the $v-t$ graph for constant velocity and explain it.

In the following displacement $x$ versus time $t$ graph,at which among the points $P, Q$ and $R$ is the object's speed increasing?