The I.P. of a hydrogen-like species is 36 eV | vedclass

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(C) The ionization potential $(I.P.)$ of a hydrogen-like species is given by $E_n = -13.6 	imes Z^2 / n^2 \ eV$. For the ground state $(n=1)$,$I.P. =

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$32$

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(C) The ionization potential $(I.P.)$ of a hydrogen-like species is given by $E_n = -13.6 	imes Z^2 / n^2 \ eV$. For the ground state $(n=1)$,$I.P. = 13.6 	imes Z^2 = 36 \ eV$. The energy of any state $n$ is $E_n = -36 / n^2 \ eV$. The second excitation energy corresponds to the transition from the ground state $(n=1)$ to the third energy level $(n=3)$. The energy of the third level is $E_3 = -36 / 3^2 = -36 / 9 = -4 \ eV$. The energy of the ground state is $E_1 = -36 / 1^2 = -36 \ eV$. The second excitation energy is $\Delta E = E_3 - E_1 = -4 - (-36) = 32 \ eV$.

The $I.P.$ of a hydrogen-like species is $36 \ eV$. What is the value of the second excitation energy in $eV$?

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