The $pH$ of $10^{-5} \ M$ aqueous solution of $NaOH$ is

$200 \ mL$ of an aqueous solution of $HCl$ $(pH=2)$ is mixed with $300 \ mL$ of aqueous solution of $NaOH$ $(pH=12)$ and is diluted to $1.0 \ L$. The $pH$ of the resulting solution is

Which of the following solutions will have the maximum $pH$?

Calculate the $pH$ of the following solutions:
$(a)$ $2 \,g$ of $TlOH$ dissolved in water to give $2 \,L$ of solution.
$(b)$ $0.3 \,g$ of $Ca(OH)_2$ dissolved in water to give $500 \,mL$ of solution.
$(c)$ $0.3 \,g$ of $NaOH$ dissolved in water to give $200 \,mL$ of solution.
$(d)$ $1 \,mL$ of $13.6 \,M \,HCl$ is diluted with water to give $1 \,L$ of solution.

The $pH$ of a solution obtained by mixing $10 \ mL$ of $0.1 \ M$ $HCl$ and $40 \ mL$ of $0.2 \ M$ $H_2SO_4$ is (Given $\log 17 = 1.23, \log 5 = 0.7, \log 10 = 1$)

The $pH$ of a $10^{-8} \ M \ HCl$ aqueous solution is ......