The $\Delta S$ for the vaporisation of $1 \ mol$ of water is $88.3 \ J/mol \ K$. The value of $\Delta S$ for the condensation of $1 \ mol$ of vapour will be.......$ J/mol \ K$
- A$88.3$
- B$(88.3)^2$
- C$-88.3$
- D$\frac{1}{88.3}$
Explore More
Similar Questions
The value of entropy of the universe is
For the process $H_2O(\ell) \rightarrow H_2O_{(g)}$ at $T = 100^{\circ} C$ and $1 \ atm$ pressure,the correct choice is:
DifficultIIT 2014
View SolutionThe enthalpy of fusion of water is $1.435 \ kcal/mol$. The molar entropy change for the melting of ice at $0 \ ^\circ C$ is
One mole of $NaCl$ $(s)$ on melting absorbed $30.5 \ kJ$ of heat and its entropy increased by $28.8 \ J \ K^{-1}$. The melting point of $NaCl$ is ............. $K$.
Medium
View SolutionWhich of the following has the highest entropy per mole?
Medium
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo