(D) The $H-O-H$ bond angle in a water molecule is approximately $104.5^\circ$ (often rounded to $105^\circ$).This deviation from the ideal tetrahedral

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(D) The $H-O-H$ bond angle in a water molecule is approximately $104.5^\circ$ (often rounded to $105^\circ$).This deviation from the ideal tetrahedral angle of $109.5^\circ$ is due to the presence of two lone pairs of electrons on the oxygen atom,which exert greater repulsion on the bonding pairs according to the $VSEPR$ theory.