The $pH$ of milk,black coffee,tomato juice,lemon juice and egg white are $6.8, 5.0, 4.2, 2.2$ and $7.8$ respectively. Calculate the corresponding hydrogen ion concentration $[H^+]$ in each.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
The hydrogen ion concentration $[H^+]$ is calculated using the formula: $pH = -\log [H^+]$,which implies $[H^+] = 10^{-pH}$.
$(i)$ For milk $(pH = 6.8)$: $[H^+] = 10^{-6.8} = 1.58 \times 10^{-7} \, M$
$(ii)$ For black coffee $(pH = 5.0)$: $[H^+] = 10^{-5.0} = 1.0 \times 10^{-5} \, M$
$(iii)$ For tomato juice $(pH = 4.2)$: $[H^+] = 10^{-4.2} = 6.31 \times 10^{-5} \, M$
$(iv)$ For lemon juice $(pH = 2.2)$: $[H^+] = 10^{-2.2} = 6.31 \times 10^{-3} \, M$
$(v)$ For egg white $(pH = 7.8)$: $[H^+] = 10^{-7.8} = 1.58 \times 10^{-8} \, M$

Explore More

Similar Questions

The value of the ionic product of water $(K_w)$ at $393 \ K$ is:

The $pH$ of a solution is increased from $3$ to $6$. Its ${H^{+}}$ ion concentration will be

$pH$ scale was introduced by

Calculate the concentration of $H^{+}$ ions in a solution if $pOH$ is $11$.

The ionic product of water at $25\,^{\circ}C$ is $10^{-14}$. The ionic product at $90\,^{\circ}C$ will be

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo