The IUPAC name for the following compound is: | vedclass

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(A) $1$. Identify the principal functional group: The compound contains a carboxylic acid $(-COOH)$ group and an aldehyde $(-CHO)$ group. According to

Vedclass · Accepted Answer

$2,5-$dimethyl$-6-$oxo$-hex-3-$enoic acid

Vedclass · Answer

(A) $1$. Identify the principal functional group: The compound contains a carboxylic acid $(-COOH)$ group and an aldehyde $(-CHO)$ group. According to $IUPAC$ priority rules,the carboxylic acid group has higher priority than the aldehyde group. Therefore,the parent chain must include the carbon of the $-COOH$ group,and the suffix will be $-oic \ acid$.
$2$. Number the carbon chain: Start numbering from the carboxylic acid carbon as $C-1$. The longest chain containing the principal functional group and the double bond is a $6-$carbon chain.
$3$. Identify substituents: The aldehyde group at $C-6$ is treated as a substituent and named as $oxo-$. There is a methyl group at $C-2$ and another methyl group at $C-5$.
$4$. Assemble the name: The substituents are $2,5-$dimethyl and $6-oxo$. The double bond is at $C-3$. Combining these,the name is $2,5-$dimethyl$-6-$oxo$-hex-3-$enoic acid.

The $IUPAC$ name for the following compound is:

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Name the following compounds according to the $IUPAC$ system:
$(i)$ $CH_3-CH(CH_2Cl)-CH(CH_2OH)-CH(CH_3)-CH_3$
$(ii)$ $CH_3-CH(CH_3)-CH_2-CH(OH)-CH(CH_2OH)-CH_3$
$(iii)$ $3-$Bromocyclohexanol (structure implied)
$(iv)$ $H_2C=CH-CH(OH)-CH_2-CH_2-CH_3$
$(v)$ $CH_3-C(CH_3)=C(Br)-CH_2OH$

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What is the $IUPAC$ name of the following compound?

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