The IUPAC name of the compound having structu | vedclass

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(B) The given structure is $C_2H_5-C(=CH_2)-CH(CH_3)-CH_3$. To find the $IUPAC$ name,we first identify the longest carbon chain containing the double

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$2-$ethyl$-3-$methylbut$-1-$ene

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(B) The given structure is $C_2H_5-C(=CH_2)-CH(CH_3)-CH_3$. To find the $IUPAC$ name,we first identify the longest carbon chain containing the double bond. The longest chain has $5$ carbon atoms,so the parent alkane is pentene. Numbering the chain from the end closer to the double bond gives the double bond at position $1$. The structure is $CH_3-CH_2-C(=CH_2)-CH(CH_3)-CH_3$. Numbering from the right: $C_5H_3-C_4H_2-C_3(=CH_2)-C_2H(CH_3)-C_1H_3$ is incorrect. Correct numbering: $CH_3(5)-CH_2(4)-C(3)(=CH_2(1))-CH(CH_3)(2)-CH_3(1)$ is not right. Let's re-examine the longest chain: $CH_3-CH_2-C(=CH_2)-CH(CH_3)-CH_3$. The longest chain is $5$ carbons long: $CH_3-CH_2-C(=CH_2)-CH(CH_3)-CH_3$. Numbering to give the double bond the lowest locant: $CH_3(5)-CH_2(4)-C(3)(=CH_2(1))-CH(CH_3)(2)-CH_3(1)$ is wrong. The longest chain is $CH_3-CH_2-C(=CH_2)-CH(CH_3)-CH_3$ which is $2-$ethyl$-3-$methylbut$-1-$ene. Wait,the longest chain is $5$ carbons: $CH_3-CH_2-C(=CH_2)-CH(CH_3)-CH_3$. Actually,the longest chain is $5$ carbons: $CH_3-CH_2-C(=CH_2)-CH(CH_3)-CH_3$. The correct $IUPAC$ name is $2-$ethyl$-3-$methylbut$-1-$ene.

The $IUPAC$ name of the compound having structure $C_2H_5-C(=CH_2)-CH(CH_3)-CH_3$ is

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