The B.G. on a certain sum due in 5 text{ year | vedclass

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(D) Let $B.D. = 1$.Given that $B.G. = \frac{3}{23} 	imes B.D. = \frac{3}{23}$.We know that $T.D. = B.D. - B.G. = 1 - \frac{3}{23} = \frac{20}{23}$.Th

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(D) Let $B.D. = 1$.Given that $B.G. = \frac{3}{23} 	imes B.D. = \frac{3}{23}$.We know that $T.D. = B.D. - B.G. = 1 - \frac{3}{23} = \frac{20}{23}$.The sum is given by the formula $Sum = \frac{B.D. 	imes T.D.}{B.D. - T.D.} = \frac{1 	imes \frac{20}{23}}{1 - \frac{20}{23}} = \frac{20/23}{3/23} = \frac{20}{3}$.Now,$S.I.$ on the sum $\frac{20}{3}$ for $5 	ext{ years}$ is equal to $T.D. = \frac{20}{23}$ (Wait,the standard relation is $S.I. = T.D.$ for the same sum and time).Actually,$S.I. = \frac{P 	imes R 	imes T}{100}$. Here $P = \frac{20}{3}$,$T = 5$,and $S.I. = T.D. = \frac{20}{23}$.$\frac{20}{23} = \frac{(20/3) 	imes R 	imes 5}{100}$.$\frac{20}{23} = \frac{100 	imes R}{300} = \frac{R}{3}$.$R = \frac{20 	imes 3}{23} \approx 2.6\%$. Re-evaluating the standard formula: $Rate = \frac{B.G. 	imes 100}{T.D. 	imes T} = \frac{(3/23) 	imes 100}{(20/23) 	imes 5} = \frac{300}{100} = 3\%$.Thus,the rate of interest is $3\%$.

The $B.G.$ on a certain sum due in $5 \text{ years}$ is $\frac{3}{23}$ of $B.D.$ Here,the rate of interest is (in $\%$):

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