The C - H bond length is minimum in the bond | vedclass

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(A) The bond length decreases as the $s$-character of the hybrid orbital increases. An $s$-orbital is closer to the nucleus than a $p$-orbital,so high

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$sp - s$ overlapping (as in alkynes)

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(A) The bond length decreases as the $s$-character of the hybrid orbital increases. An $s$-orbital is closer to the nucleus than a $p$-orbital,so higher $s$-character results in a shorter bond length. $sp$ hybridization has $50\% \ s$-character,$sp^2$ has $33.3\% \ s$-character,and $sp^3$ has $25\% \ s$-character. Therefore,the $C - H$ bond length is minimum in $sp - s$ overlapping (alkynes). CompoundHybridization$C - H$ bond length $(\mathring{A})$Alkane$sp^3$$1.093$Alkene$sp^2$$1.087$Alkyne$sp$$1.057$

The $C - H$ bond length is minimum in the bond formed by

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