The 20^{th} term of the A.P. 2, -2, -6, -10, | vedclass

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(A) The given $A.P.$ is $2, -2, -6, -10, \ldots$Here,the first term $a = 2$.The common difference $d = a_2 - a_1 = -2 - 2 = -4$.The formula for the $n

Vedclass · Accepted Answer

$-74$

Vedclass · Answer

(A) The given $A.P.$ is $2, -2, -6, -10, \ldots$Here,the first term $a = 2$.The common difference $d = a_2 - a_1 = -2 - 2 = -4$.The formula for the $n^{th}$ term of an $A.P.$ is $a_n = a + (n - 1)d$.To find the $20^{th}$ term $(n = 20)$:$a_{20} = 2 + (20 - 1)(-4)$$a_{20} = 2 + (19)(-4)$$a_{20} = 2 - 76$$a_{20} = -74$.Therefore,the $20^{th}$ term is $-74$.

The $20^{th}$ term of the $A.P.$ $2, -2, -6, -10, \ldots$ is.......

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